The molarity or molar concentration
The molarity or molar concentration
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The molarity or molar concentration
MOLARITY
The molarity (or molar concentration) of a solution is the number of moles of solute dissolved in 1 L of solution. It is expressed in moles per litre (mol/L, or M)
Molarity = amount of solute (in mol)
volume of solution (in L)
or: C = n
V
Calculating Molarity – Example 1
Calculate the molarity of a solution that consists of 12.3 g of potassium nitrate dissolved in 50 ml of water.
Solution
First, you need to find the number of moles of potassium nitrate (KNO3).
M (KNO3) = 39.10 + 14.01 + 3(16.00)
= 101.11 g/mol
n = 12.3 g
101.11 g/mol
= 0.1216 mol
Divide the number of moles by the number of litres.
50 ml/1000 = 0.050 L
C = 0.1216 mol
0.05 L
= 2.43 mol/L
The molarity of the solution is 2.43 mol/L.
Example 2
Calculate the mass of NaCl required to prepare 250 ml of a 0.850 mol/L solution.
Solution
First you need to calculate the number of moles of NaCl, using the concentration and volume.
C = n/V à n = VxC
= (0.250 L)(0.850 mol/L)
= 0.212 mol
M (NaCl) = 22.99 + 35.45
= 58.44 g/mol
m = (0.212 mol)(58.44 g/mol)
= 12.4 g
p. 316 19-24
Source : http://taverner.wikispaces.com/file/view/MOLARITY.doc
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The molarity or molar concentration
Another Mole Concept: The Molar Concentration
Some Definitions you need to remember:
Solution: homogeneous mixture of two or more substances.
Solvent: the component of a solution that exists in greater quantity.
Solute: the component of the solution that exists in smaller quantity.
Concentration: amount of a substance present in a given volume of solution.
Concentrated: has relatively large amount of substance present in a given volume of solution.
Dilute: has relatively small amount of substance present in a given volume of solution.
Molar concentration or Molarity: number of moles of a particular substance in one liter of solution.
Unit for Molarity: “mole/L” or “M”
1.0 M is read as “ 1.0 MOLAR”
Symbol for concentration: [ ] e.g. [NaCl] = 1.2 M
The Formula for concentration:
Molar Concentration (c) = moles (n) c = molar concentration
Volume (V) n = number of moles
V = volume, in litres
Source : http://www.msdiehl.com/resources/molar+concentration+notes.doc
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The molarity or molar concentration
Molarity & Dilutions Notes
Concentration: Measure of how much solute is dissolved in a specific amount of solvent/solution.
- A concentrated solution contains larger amount of solute
- A dilute solution contains a smaller amount of solute
Molarity (M): moles of solute / liters of solution
- Also know as molar concentration
- It’s unit is M (read/pronounced a molar)
Example:
1) What is the molar concentration of a liter solution with 0.5 mol of solute?
Molarity = moles of solute / liter of solution
= 0.5 mol solute / 1 L solution
= 0.5 M
- A 100.5 mL IV solution containing 5.10g glucose (C6H12O6). What is the molarity of the solution? (MM of glucose = 180.16 g/mol)
Molarity = moles of solute / liter of solution
Step 1: convert grams of solute glucose to moles solute using MM of glucose
5.10 g glucose x 1 mole glucose = 0.0283 mol glucose
180.16 g glucose
Step 2: convert mL of solution to Liters of solution
(Remember week 1 notes: here we’re going from milliliters to liters so we’re going to a higher prefix this means we’re moving the decimal to the left 3 decimal places)
100.5 mL = 0.1005 L
Step 3: solve for molarity
M = moles of solute/ liters of solution
= 0.0283 mol glucose / 0.1005 L solution
= 0.282 M
How to prepare a molar solution:
Given the desired molarity and volume you can mix a solution by:
Refer to example from class.
Also see p. 484 of text
Dilutions: Adding additional solvent to dilute a more concentrated stock solution.
- The total # of moles of solute does not change during a dilution (only solvent is added)
Dilution Equation:
M1V1 = M2V2
M1 = the initial molarity of the concentrated solution
V1 = the initial volume of the concentrated solution
M2 = the final molarity of the dilute solution
V2 = the final molarity of the dilute solution
Example:
What volume of 2.00 M CaCl2 stock solution would you use to make 0.50 L of 0.300 M CaCl2?
M1V1 = M2V2
M1 = 2.00 M
V1 = ?
M2 = 0.300 M
V2 = 0.50 L
2.00 M x V1 = 0.300M x 0.50L
V1 = 0.075 L
Source : http://chemistry2008.pbworks.com/f/Molarity+notes.doc
Web site link: http://chemistry2008.pbworks.com
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